Find the positions relative to a set.
Find positions of $\dfrac{1}z$, $\bar{z}$ and $-z$ on a set $|z|=2^2$?
The position of $\dfrac{1}z$ will be $x^2+y^2=\dfrac12$ and $\bar{z}$ will
be $x^2+y^2=2$ (which have no effect) and $-z=|-z|=|z|$ (which also have
no effect).
Can someone please confirm if I'm right.
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